Réaction #312585

ord-e340a01c97f3477caf8d844c91753b25

Équation de réaction

O=C(CBr)c1ccccc1
phenacyl bromide
C1CCSC1
tetrahydrothiophene
O
water
CCOCC
diethyl ether
O=C(C[S+]1CCCC1)c1ccccc1.[Br-]
phenacyltetrahydrothiophenium bromide

Solvants

Conditions de réaction

Conditions détaillées
See reaction.notes.procedure_details.

Traitement

  1. 1
    Autreseparated into two layers

Mode opératoire

88.2 g (0.44 mole) of phenacyl bromide and 39.1 g (0.44 mole) of tetrahydrothiophene were dissolved in 220 g of nitromethane, which was stirred for 4 hours at room temperature. 800 g of water and 400 g of diethyl ether were added to the reaction solution whereupon the mixture separated into two layers. The aqueous layer was taken out, which was an aqueous solution of the target compound, phenacyltetrahydrothiophenium bromide.

Source

DOI: 10.6084/m9.figshare.5104873.v1Brevet: US07556909B2uspto-grants-2009_07