Réaction #1448231
ord-bbcc6eb5f8ad40e4b640f7efd6e964d9
Équation de réaction
2-bromo-hexanoic acid methyl ester
4-fluoro-3-methylphenol
K2CO3
→
title compound
Rendement 76.4%
2-(4-Fluoro-3-methyl-phenoxy)-hexanoic acid methyl ester
Rendement 76.4%
Réactifs
Aucun
Conditions de réaction
Conditions détaillées
See reaction.notes.procedure_details.
Traitement
- 1Extractionextracted with dichloromethane (60 mL×3)
- 2Séchagedried over anhydrous Na2SO4
- 3AutreAfter removing the solvent under reduced pressure
- 4Autrethe product was isolated by Flash chromatography (silica gel)
- 5Lavageeluting with 0-20% ethyl acetate/hexanes
Mode opératoire
To a solution of 2-bromo-hexanoic acid methyl ester (0.500 g, 2.404 mmol) and 4-fluoro-3-methylphenol (0.303 g, 2.404 mmol) in 15 mL of DMF, was added K2CO3 (1.661 g, 12.020 mmol). After stirring at room temperature under N2 for 88 h, the reaction mixture was diluted with 60 mL of water and extracted with dichloromethane (60 mL×3). The organic extracts were combined and dried over anhydrous Na2SO4. After removing the solvent under reduced pressure, the product was isolated by Flash chromatography (silica gel) eluting with 0-20% ethyl acetate/hexanes to give the title compound as yellow oil (0.467 g, 76% yield). LC-MS: tR=10.5 min; m/z 255 (M+H)+.