Réaction #1106631

Équation de réaction

2-hydroxyacetophenone

furan-2-carbaldehyde

NaOCH3

THF

→

chalcone

Rendement 71.0%

Conditions de réaction

Mode opératoire

2.27 g (16.7 mmol) of 2-hydroxyacetophenone, 1.52 g of furan-2-carbaldehyde (15.8 mmol), and 10 ml of 25% wt NaOCH3 were reacted in 50 ml of dry THF to give 2.4 g (71%) of chalcone after purification. 1H NMR (300 MHz, CDCl3): δ 12.90 (s, 1H), 7.94 (d, d, J=1.5, 8.1 Hz, 1H), 7.71 (d, J=15.0 Hz, 1H), 7.58 (d, J=15.0 Hz, 1H), 7.58 (d. J=1.5 Hz, 1H), 7.51 (d, d, d, J=1.5, 7.2, 8.4 Hz, 1H), 7.04 (d, d, J=0.9, 8.4 Hz, 1H), 6.96 (d, d, J=8.1, 8.1 Hz, 1H), 6.79 (d, J=3.3 Hz, 1H), 6.56 (d, d, J=1.5, 3.3 Hz, 1H).

Source