Reacción #577228

ord-171c3d7f83144f5bbbe8d5ff203f9d5f

Ecuación de reacción

O=C(CBr)c1ccccc1
phenacyl bromide
C1CCSC1
tetrahydrothiophene
O
water
CCOCC
diethyl ether
O=C(C[S+]1CCCC1)c1ccccc1.[Br-]
Phenacyltetrahydrothiophenium Bromide

Disolventes

Condiciones de reacción

Condiciones detalladas
See reaction.notes.procedure_details.

Tratamiento posterior

  1. 1
    Otroseparated into two layers

Procedimiento

88.2 g (0.44 mole) of phenacyl bromide and 39.1 g (0.44 mole) of tetrahydrothiophene were dissolved in 220 g of nitromethane, which was stirred for 4 hours at room temperature. 800 g of water and 400 g of diethyl ether were added to the reaction solution whereupon the mixture separated into two layers. The aqueous layer was taken out, which was an aqueous solution of the target compound, phenacyltetrahydrothiophenium bromide.

Fuente

DOI: 10.6084/m9.figshare.5104873.v1Patente: US07527912B2uspto-grants-2009_05