Reaction #2348122

Reaction equation

NaOH

Thiophenol

trans-stilbene

NMP

K2CO3

→

5-[(E)-2-(4-hydroxyphenyl)-vinyl]-pyridin-2-ol

Yield 69.0%

Conditions

Workup

1. 1
   OtherThe cooled reaction mixture
2. 2
   Extractionthe neutral components were extracted with ether (3×50 mL)
3. 3
   Extractionextracted with ether (2×50 mL)
4. 4
   OtherThe solid was isolated by filtration
5. 5
   Washwashed with water (100 mL), ethyl acetate (50 mL) and ether (30 mL)
6. 6
   Otherair-dried

Procedure

The trans-stilbene (1.17 g, 4.85 mmol) was dissolved in dry NMP (12 mL). Thiophenol (1.07 g, 9.7 mmol) was then added to the above solution, followed by addition of K2CO3 (67 mg, 0.48 mmol). The resulting mixture was heated for 8 hours at 195° C. under nitrogen. The cooled reaction mixture was made alkaline with 1 N NaOH (pH=10), and the neutral components were extracted with ether (3×50 mL). The aqueous layer was acidified to pH=4 with 1 N HCl and stirred at room temperature for 30 minutes, and extracted with ether (2×50 mL). Then pH was adjusted to pH=8 with saturated NaHCO3. The solid was isolated by filtration, washed with water (100 mL), ethyl acetate (50 mL) and ether (30 mL), and air-dried to yield 5-[(E)-2-(4-hydroxyphenyl)-vinyl]-pyridin-2-ol (715 mg, 69%). MS (ES) m/z: 214.08 (M+1); 13C-NMR (DMSO-d6): δ 162.42, 157.50, 138.21, 134.07, 129.04, 127.92, 125.67, 121.59, 121.03, 116.89, and 116.18.

Source