Reaction #172379
ord-0bcd3dacdb0645a89ab81d6c03ce4396
Reaction equation
Reagents
None
Conditions
Detailed conditions
See reaction.notes.procedure_details.
Procedure
Analogously to Example 4A, 1.50 g (4.13 mmol) of the compound from Example 3A are reacted with 704 mg (4.54 mmol) of 2-fluoro-5-nitrotoluene. This gives 570 mg (28% of theory) of the title compound.