Reaction #1702094

Reaction equation

(2-Benzyloxycarbonylamino-ethyl)-methyl-phosphinic acid ethyl ester

EtOH

→

(2-amino-ethyl)-methyl-phosphinic acid ethyl ester

Yield 90.0%

Solvents

EtOAc

Conditions

Workup

1. 1
   Otherwas run at room temperature
2. 2
   FiltrationThe reaction was then filtered through Supercell NF
3. 3
   Concentrationthe filtrate was concentrated

Procedure

(2-Benzyloxycarbonylamino-ethyl)-methyl-phosphinic acid ethyl ester (1.3 g, 4.56 mmol) and 10% Pd/C (485 mg) were combined in a flask and EtOH (46 mL) was added. The reaction flask atmosphere was exchanged for H2 and the reaction was run at room temperature until complete, as determined by TLC (eluent: 100% EtOAc). The reaction was then filtered through Supercell NF and the filtrate was concentrated to yield (2-amino-ethyl)-methyl-phosphinic acid ethyl ester (615 mg, 90%) as a yellow oil in which white crystals began to form under high vacuum.

Source