Reaction #1203

ord-540e2d8dfa8f4e3c817851023a8dc240

Reaction equation

CCCCCCC(O)CCCCCCCCCCCCC(O)CN(C)CCO
1-[N-Methyl-N-(2-hydroxyethyl)amino]-3-(12-hydroxyoctadecyl)-2-propanol
CCCCCCC(O)CCCCCCCCCCCOCC1CO1
12-hydroxyoctadecyl glycidyl ether
CNCCO
N-methylethanolamine
COCC(O)CN(C)CCO
N-(3-methoxy-2-hydroxy-propyl)-N-methyl-2-hydroxyethylamine
CBr
methyl bromide
CCCCCCC(O)CCCCCCCCCCCCC(O)C[N+](C)(C)CC(C)O.[Br-]
title compound
Yield 90.0%
CCCCCCC(O)CCCCCCCCCCCCC(O)C[N+](C)(C)CC(C)O.[Br-]
N-(2-hydroxypropyl)-N,N-dimethyl-N-[3-(12-hydroxyoctadecyl)-2-hydroxypropyl]ammonium bromide
Yield 90.0%

Conditions

Detailed conditions
See reaction.notes.procedure_details.

Workup

  1. 1
    ConcentrationThe reaction mixture was then concentrated under reduced pressure
  2. 2
    workup.DISSOLUTIONthe resultant residue was dissolved in methanol
  3. 3
    workup.ADDITIONDiethyl ether was added to the solution
  4. 4
    Otherto form crystals
  5. 5
    FiltrationThe crystals were collected by filtration

Procedure

1-[N-Methyl-N-(2-hydroxyethyl)amino]-3-(12-hydroxyoctadecyl)-2-propanol was first prepared from 12-hydroxyoctadecyl glycidyl ether and N-methylethanolamine in the same manner as in the preparation of N-(3-methoxy-2-hydroxy-propyl)-N-methyl-2-hydroxyethylamine in Preparation Example 24. A 200-ml autoclave was charged with 6.3 g (15 mmol) of the thus-prepared compound, 100 ml of diethyl ether and 14.2 g of methyl bromide, and the resultant mixture was stirred at 48° C. for 8 hours. The reaction mixture was then concentrated under reduced pressure, and the resultant residue was dissolved in methanol. Diethyl ether was added to the solution to form crystals. The crystals were collected by filtration, thereby obtaining 6.9 g (yield: 90%) of the title compound (IIb-4).

Source

DOI: 10.6084/m9.figshare.5104873.v1Patent: US05723497uspto-grants-1998_03