Reaktion #93699

Reaktionsgleichung

hydrochloric acid

3-bromopropyl phenyl ether

thiourea

potassium hydroxide

→

3-phenoxypropanethiol

Ausbeute 61.1%

Lösungsmittel

ethanol

methanol

Reaktionsbedingungen

Aufarbeitung

1. 1
   Temperaturthe solution was refluxed
2. 2
   Temperaturwith heating for 3 hours
3. 3
   workup.ADDITIONwas added to the reaction solution
4. 4
   Extraktionextracted with ethyl acetate
5. 5
   workup.DISTILLATIONfollowed by distillation under reduced pressure

Vorschrift

160 g of 3-bromopropyl phenyl ether and 63 g of thiourea were dissolved in 300 ml of ethanol and the solution was refluxed with heating for 3 hours. A methanol solution containing 194 g of potassium hydroxide was added to the reaction solution and the mixture was stirred at 50° C. for 2 hours. The mixture was poured into diluted hydrochloric acid and extracted with ethyl acetate followed by distillation under reduced pressure to obtain 76.5 g of 3-phenoxypropanethiol. A boiling point was 135° to 138° C. at 17 mm Hg.

Quelle