Reaktion #8513

Reaktionsgleichung

1,5-bis(4-nitrophenoxy)pentane

hydrogen

→

1,5-bis(4-aminophenoxy)pentane

Ausbeute 90.0%

Lösungsmittel

tetrahydrofuran

Reaktionsbedingungen

Aufarbeitung

1. 1
   Sonstigeprepared
2. 2
   FiltrationThe mixture was then filtered over CELITE
3. 3
   Sonstigethe solvent was removed by evaporation under reduced pressure
4. 4
   SonstigeThe resulting crude solid was recrystallized from ethanol

Vorschrift

A mixture of 1,5-bis(4-nitrophenoxy)pentane (32.7 grams, 94.4 mmol; prepared as described in Part A of this Example) and Pd/C 10% (1.00 gram, obtained from Aldrich Chemical Co.) was stirred for 20 hours in tetrahydrofuran (400 milliliters) under 200 pounds per square inch of hydrogen gas. The mixture was then filtered over CELITE, and the solvent was removed by evaporation under reduced pressure. The resulting crude solid was recrystallized from ethanol to afford pure 1,5-bis(4-aminophenoxy)pentane (24.4 grams, 85.1 mmol, 90 percent yield) as small colorless crystals: mp 78–79° C.; IR (KBr) 3433, 3353, 3217, 2949, 2868, 1856, 1632, 1511, 1473, 1396, 1228, 1031, 1002, 825, 517 cm−1; 1H NMR (300 MHz, CDCl3) δ 6.76 (d, 4H, 3J=8.8 Hz), 6.64 (d, 4H, 3J=8.8 Hz), 3.92 (td, 4H, 3J=6.4 Hz, 4J=1.4 Hz), 3.40 (s, 4H), 1.82 (q, 4H, 3J=6.8 Hz), 1.62 (q, 2H, 3J=6.8 Hz); 13C NMR (75 MHz, CDCl3) δ 151.31, 140.06, 116.51, 115.78, 68.58, 29.32, 22.83; MS (FAB, 3-nitrobenzyl alcohol) m/e 286.7; Anal. Calcd for C17H22N2O2: C, 71.30; H, 7.74; N, 9.78. Found: C, 71.11; H, 8.22; N, 9.85.

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