Reaktion #84345

Reaktionsgleichung

Iodomethane

Sodium hydride

4-fluorophenethyl alcohol

NH4Cl

→

title product

Ausbeute 45.2%

1-fluoro-4-(2-methoxyethyl)benzene

Ausbeute 45.2%

Lösungsmittel

THF

Reaktionsbedingungen

Aufarbeitung

1. 1
   workup.ADDITIONAt the end of the addition
2. 2
   Temperaturcooled to 0° C
3. 3
   workup.STIRRINGthe reaction mixture was stirred overnight
4. 4
   SonstigeUpon the completion of the reaction
5. 5
   Temperaturthe mixture was cooled to 0° C.
6. 6
   Extraktionextracted with EtOAc (3×25 mL)
7. 7
   WaschenThe combined extracts were sequentially washed with aq. sat. NH4Cl (3×20 mL), brine (20 mL)
8. 8
   Trocknendried (Na2SO4)
9. 9
   EinengenThe crude product was concentrated
10. 10
    Sonstigedried over high vacuum

Vorschrift

Sodium hydride (60% dispersion in mineral oil, 145 mg, 3.62 mmol) was slowly added to a solution of 4-fluorophenethyl alcohol (338 mg, 2.41 mmol) in THF (5 mL) at room temperature and with stirring. At the end of the addition, the solution had become cloudy. The reaction mixture was heated to 60° C. for 2 h and then cooled to 0° C. Iodomethane (225 μL, 3.62 mmol) was slowly added to the solution and the reaction mixture was stirred overnight. Upon the completion of the reaction, the mixture was cooled to 0° C., neutralized with aq. sat. NH4Cl (25 mL) and extracted with EtOAc (3×25 mL). The combined extracts were sequentially washed with aq. sat. NH4Cl (3×20 mL), brine (20 mL) and dried (Na2SO4). The crude product was concentrated and dried over high vacuum. Chromatography of the residue (EtOAc/hexanes=1/3) gave 169 mg (1.09 mmol) of the title product. Yield: 45%, pale yellow oil. 1H NMR (300 MHz, CDCl3): δ 7.18 (dd, J=8.5, 5.6, Hz, 2H), 6.98 (apparent t, J=8.7 Hz, 2H), 3.58 (t, J=6.9 Hz, 2H), 3.36 (s, 3H), 2.86 (t, J=6.9 Hz, 2H) ppm. 13C NMR (75 MHz, CDCl3): δ 161.7 (d, J=242.2 Hz), 134.8 (d, J=3.2 Hz), 130.4 (d, J=7.7 Hz), 115.3 (d, J=20.9 Hz), 73.7, 58.8, 35.5 ppm. 19F NMR (282 MHz, CDCl3): δ −113.3 (m) ppm.

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