Reaktion #83540

Reaktionsgleichung

sodium hypochlorite

3-(3-hydroxy-2-pyridyl)-propionic acid methyl ester

sodium iodide

→

3-(3-hydroxy-6-iodo-2-pyridyl)-propionic acid methyl ester

Ausbeute 32.7%

Lösungsmittel

methanol

Reaktionsbedingungen

Aufarbeitung

1. 1
   EinengenThe yellow suspension is concentrated by evaporation
2. 2
   WaschenThe organic phase is washed with 10% sodium thiosulfate solution
3. 3
   Trocknendried with sodium sulfate
4. 4
   Einengenconcentrated by evaporation
5. 5
   Sonstigethe residue is chromatographed on silica gel with hexane/0-50% ethyl acetate

Vorschrift

A solution of 15 g of 3-(3-hydroxy-2-pyridyl)-propionic acid methyl ester in 250 ml of methanol is mixed with 12.4 g of sodium iodide, cooled to 15° C., and 74 ml of aqueous sodium hypochlorite solution (6.5% active chlorine) is instilled. The yellow suspension is concentrated by evaporation, the residue is taken up in water, acidified to pH 4 with 2n sulfuric acid and shaken out with ethyl acetate. The organic phase is washed with 10% sodium thiosulfate solution, dried with sodium sulfate, concentrated by evaporation and the residue is chromatographed on silica gel with hexane/0-50% ethyl acetate. 8.3 g of 3-(3-hydroxy-6-iodo-2-pyridyl)-propionic acid methyl ester of melting point 145°-148° C. is obtained.

Quelle