Reaktion #76773

Reaktionsgleichung

2-bromo-4-fluoro-5-nitrophenyl isopropyl ether

→

4-bromo-2-fluoro-5-isopropoxyaniline

Ausbeute 95.5%

Lösungsmittel

ethyl acetate

Reaktionsbedingungen

Aufarbeitung

1. 1
   workup.ADDITIONwas added
2. 2
   SonstigeAfter completion of the reaction
3. 3
   Sonstigethe palladium-carbon was removed by filtration
4. 4
   Einengenthe filtrate was concentrated

Vorschrift

Then, 60 g (0.22 mol) of 2-bromo-4-fluoro-5-nitrophenyl isopropyl ether was dissolved in 300 ml of ethyl acetate, to which 1.0 g of 10% palladium-carbon was added, and the hydrogenation was effected under an atmosphere of hydrogen. After completion of the reaction, the palladium-carbon was removed by filtration, and the filtrate was concentrated, which afforded 52 g (0.21 mol) of 4-bromo-2-fluoro-5-isopropoxyaniline.

Quelle