Reaktion #65299

Reaktionsgleichung

H3PO4

H2O

K2CO3

α-methylstyrene

α-methylstyrene

→

(R)-2-phenyl-1.2-propanediol

Ausbeute 95.0%

Lösungsmittel

t-BuOH

Reaktionsbedingungen

Aufarbeitung

1. 1
   Sonstigeis applied at 15° C.
2. 2
   Sonstigeis consumed (the reaction
3. 3
   SonstigeThe product is isolated

Vorschrift

A flow cell reactor filled with a 100 cm2 platinum on titanium anode and a 100 cm2 stainless steel cathode--the two electrode compartment being divided by a Nafion® cation exchange membrane--is used. A solution of 5% H3PO4 is circulated through the cathode compartment, while a solution of anolyte consisting of the followings: H2O (2 liters), t-BuOH (2 liters), K3Fe(CN)6 (0.24 mole, 91 g), K2CO3 (4.8 mole, 662 g), the chiral ligand, PHAL-DHQD (0.012 mole, 9.3 g), OsO4 (0.2M in toluene, 0.0008 mole, 4 mL) and α-methylstyrene (1.6 mole, 189 g) is circulated through the anode compartment. A constant current of 3 A (current density 30 mA/cm2) is applied at 15° C. until almost all the α-methylstyrene is consumed (the reaction is followed by thin layer chromatography on silica gel). The product is isolated as described above (Example 6.1) to provide (R)-2-phenyl-1.2-propanediol in 95% yield and 90% ee.

Quelle