Reaktion #54837

Reaktionsgleichung

lithium aluminum hydride

ethyl 3-chloro-4-cyclohexylphenylglyoxylate

hydrochloric acid

→

1-(3-chloro-4-cyclohexylphenyl)-1,2-ethanediol

Lösungsmittel

ether

ether

Reaktionsbedingungen

Aufarbeitung

1. 1
   workup.STIRRINGis stirred for 2 hours
2. 2
   Extraktionextracted with ether/tetrahydrofuran
3. 3
   WaschenThe aqueous fraction is washed three times with 50 ml portions of ether
4. 4
   WaschenThe combined ether fractions are washed with water until neutral to litmus, and
5. 5
   Trocknenis dried over potassium carbonate
6. 6
   SonstigeThe ether is removed
7. 7
   Sonstigethe residue is triturated with n-hexane
8. 8
   Filtrationfiltered
9. 9
   Sonstigeair-dried

Vorschrift

To lithium aluminum hydride solution (3.9 M; 120 ml) diluted with anhydrous ether (750 ml) is added dropwise 150 g of ethyl 3-chloro-4-cyclohexylphenylglyoxylate with stirring, under nitrogen. The mixture is diluted with 250 ml of ether, and is stirred for 2 hours. The reaction mixture is acidified with 10% hydrochloric acid (450 ml) and extracted with ether/tetrahydrofuran. The aqueous fraction is washed three times with 50 ml portions of ether. The combined ether fractions are washed with water until neutral to litmus, and is dried over potassium carbonate. The ether is removed and the residue is triturated with n-hexane, filtered and air-dried to give 1-(3-chloro-4-cyclohexylphenyl)-1,2-ethanediol.

Quelle