Reaktion #522386

ord-87c9c8af31224fa5a1a3271faeae1f15

Reaktionsgleichung

Oc1ccccc1
phenol
O=C(C(F)(F)F)C(F)(F)F
hexafluoroacetone
FC(F)=C(F)C(F)(F)F
hexafluoropropene
FC(F)(F)C1(F)OC1(F)F
hexafluoropropene epoxide
FC(F)=C(F)C(F)(F)F
hexafluoropropene
Oc1ccc(C(c2ccc(O)cc2)(C(F)(F)F)C(F)(F)F)cc1
hexafluoro-2,2-bis-(4-hydroxyphenyl)-propane
Ausbeute 86.4%

Reaktionsbedingungen

Temperatur
100°CELSIUS
Detaillierte Bedingungen
See reaction.notes.procedure_details.

Aufarbeitung

  1. 1
    Temperaturthe resulting mixture was heated for 8 hours at 100° C
  2. 2
    Sonstigein the reaction
  3. 3
    workup.DISTILLATIONhad been distilled off

Vorschrift

A mixture of 228 g of hexafluoropropene epoxide and 72 g of hexafluoropropene, and also 220 g of hydrogen fluoride were filled into a 1 liter capacity stainless steel autoclave without a stirring device and the mixture was heated for 20 hours at 100° C. The reaction product, which consisted of a solution of hexafluoroacetone in hydrogen fluoride, was transferred by exploiting its own vapor pressure to a 2.7 liter capacity nickel autoclave, which already contained 258 g of phenol, and the resulting mixture was heated for 8 hours at 100° C. After the hydrogen fluoride and the hexafluoropropene, which did not take part in the reaction, had been distilled off, 399 g of hexafluoro-2,2-bis-(4-hydroxyphenyl)-propane were obtained. This corresponds to a yield of 86.4% of theory.

Quelle

DOI: 10.6084/m9.figshare.5104873.v1Patent: US04400546uspto-grants-1983_08