Reaktion #438539

Reaktionsgleichung

H2O

8

Trimethyl (2,3,2′-trifluoro-4′-iodobiphenyl-4-yl)silane

4-propylphenylboronic acid

neopentyl glycol

→

10

Ausbeute 89.0%

Terphenyl

Ausbeute 89.0%

Lösungsmittel

i-PrOH

acetone

Reaktionsbedingungen

Aufarbeitung

1. 1
   SonstigeThe solvent is subsequently removed under reduced pressure
2. 2
   workup.ADDITION5 ml of 2 M HCl are added to the residue
3. 3
   Extraktionthe mixture is extracted with dichloromethane (3×5 ml)
4. 4
   TrocknenThe combined organic phases are dried over MgSO4
5. 5
   Filtrationfiltered through SiO2
6. 6
   SonstigeThe solvent is removed under reduced pressure

Vorschrift

A solution of (2 mmol) of 8, (2.2 mmol) of 4-propylphenylboronic acid, 250 mg (2.40 mmol) of neopentyl glycol, 1.53 g (4.84 mmol) of Ba(OH)2. 8 H2O, 1.35 ml (0.103 mmol, 5 mol %) of a 76 mM acetone solution of Pd(OAc)2 in 20 ml of 95% i-PrOH is stirred at 80° C. for 12 hours. The solvent is subsequently removed under reduced pressure. 5 ml of 2 M HCl are added to the residue, and the mixture is extracted with dichloromethane (3×5 ml). The combined organic phases are dried over MgSO4 and filtered through SiO2. The solvent is removed under reduced pressure, and the residue is converted into 10 (yield: 89%).

Quelle