Reaktion #302848

ord-a9fc321af3234c989e02d762ecf9932e

Reaktionsgleichung

[Cl][Sn][Cl]
Tin(II) chloride
O=c1cc(-c2ccc([N+](=O)[O-])cc2)oc2ccc(Br)cc12
compound 4
O=c1cc(-c2ccc([N+](=O)[O-])cc2)oc2ccc(Br)cc12
6-bromo-4′-nitroflavone
[Na+].[OH-]
sodium hydroxide
Nc1ccc(-c2cc(=O)c3cc(Br)ccc3o2)cc1
compound 5
Nc1ccc(-c2cc(=O)c3cc(Br)ccc3o2)cc1
6-bromo-4′-aminoflavone

Lösungsmittel

Reaktionsbedingungen

Detaillierte Bedingungen
See reaction.notes.procedure_details.

Aufarbeitung

  1. 1
    TemperaturThe obtained mixture was heated
  2. 2
    Temperaturto reflux for 1 hour
  3. 3
    SonstigeAfter completion of the reaction
  4. 4
    Extraktionthe obtained mixture was then extracted with 50 ml (25 ml×2) of ethyl acetate
  5. 5
    TrocknenThe extract was dried over anhydrous sodium sulfate
  6. 6
    workup.DISTILLATIONthe solvent was then distilled away under reduced pressure

Vorschrift

Tin(II) chloride (275 mg, 1.45 mmol) was slowly added to an ethanol solution (7 ml) that contained compound 4 (100 mg, 0.289 mmol), while stirring. The obtained mixture was heated to reflux for 1 hour. After completion of the reaction, a 1 N sodium hydroxide aqueous solution (50 ml) was added to the reaction solution, and the obtained mixture was then extracted with 50 ml (25 ml×2) of ethyl acetate. The extract was dried over anhydrous sodium sulfate, and the solvent was then distilled away under reduced pressure, so as to obtain a product of interest, 6-bromo-4′-aminoflavone (compound 5) in the form of a yellow crystal. Yield: 77 mg (yield constant: 84.3%) 1H NMR (300 MHz, CDCl3) δ8.36 (s, 1H), 7.72-7.76 (m, 3H), 7.44 (d, J=9.0 Hz, 1H), 6.72 (d, J=8.7 Hz, 2H), 6.70 (s, 1H), 4.15 (s, 2H). MS m/z 317 (MH+).

Quelle

DOI: 10.6084/m9.figshare.5104873.v1Patent: US08192717B2uspto-grants-2012_06