Reaktion #1890

Reaktionsgleichung

lithium aluminum hydride

5-chloro-α-(2-chlorophenyl)-2-(trifluoroacetylamino)benzyl alcohol

water

→

oily compound

Ausbeute 86.7%

5-chloro-α-(2-chlorophenyl)-2-(2,2,2-trifluoroethylamino)benzyl alcohol

Ausbeute 86.7%

Lösungsmittel

ethyl ether

tetrahydrofuran

Reaktionsbedingungen

Aufarbeitung

1. 1
   Sonstigethe organic layer was dried
2. 2
   Sonstigeafter which the solvent was removed

Vorschrift

To a suspension of 0.25 g of lithium aluminum hydride in 20 ml of absolute ethyl ether, a solution of 1.2 g of 5-chloro-α-(2-chlorophenyl)-2-(trifluoroacetylamino)benzyl alcohol in 5 ml of tetrahydrofuran was added dropwise. After mixture stirring at room temperature for 1 hour, water was added, and the organic layer was dried, after which the solvent was removed and the residue was subjected to silica gel column chromatography to yield 1.0 g of an oily compound.

Quelle