Reaktion #172379
ord-0bcd3dacdb0645a89ab81d6c03ce4396
Reaktionsgleichung
Reagenzien
Keine
Reaktionsbedingungen
Detaillierte Bedingungen
See reaction.notes.procedure_details.
Vorschrift
Analogously to Example 4A, 1.50 g (4.13 mmol) of the compound from Example 3A are reacted with 704 mg (4.54 mmol) of 2-fluoro-5-nitrotoluene. This gives 570 mg (28% of theory) of the title compound.