Reaktion #1280

Reaktionsgleichung

hexafluoropropene

oleum

→

HFP sultone

Ausbeute 65.0%

Reaktionsbedingungen

Aufarbeitung

1. 1
   Sonstigethe sultone layer (95.0 g) was separated
2. 2
   workup.DISTILLATIONdistilled

Vorschrift

Using essentially the procedure of Example 1, the reactor was charged with 44.7 g hexafluoropropene, 45.9 g of 67 wt. % oleum and 41.5 g Fluorinert FC-77™. The reaction mixture was heated at 50° C. for 6 hours. The reactor was vented of excess HFP and the sultone layer (95.0 g) was separated and distilled to provide the HFP sultone (45 g, b.p. 48°-52° C., purity 93% by gc). The yield was 65% based on consumed HFP.

Quelle