تفاعل #986940

معادلة التفاعل

3-(1H-imidazol-4-yl)-propionic acid

H2SO4

MeOH

→

oil

المردود 90.0%

3-(1H-Imidazol-4-yl)-propionic acid methyl ester

المردود 90.0%

ظروف التفاعل

المعالجة

1. 1
   درجة الحرارةat reflux for 15 h
2. 2
   تركيزconcentrated in vacuo
3. 3
   workup.DISSOLUTIONThe residue was dissolved in CH2Cl2 (40 mL)
4. 4
   غسيلwashed with saturated NaHCO3(aq) (30 mL)
5. 5
   استخلاصextracted with EtOAc (4×25 mL)
6. 6
   تجفيفThe combined organic phases were dried (MgSO4)
7. 7
   تركيزconcentrated in vacuo

الإجراء التجريبي

A solution of 3-(1H-imidazol-4-yl)-propionic acid (1.95 g, 13.9 mmol) and H2SO4 (catalytic) in MeOH (30 mL) was heated at reflux for 15 h, then concentrated in vacuo. The residue was dissolved in CH2Cl2 (40 mL) and washed with saturated NaHCO3(aq) (30 mL). The aqueous phase was saturated with sodium chloride and extracted with EtOAc (4×25 mL). The combined organic phases were dried (MgSO4) and concentrated in vacuo to give a yellow oil (1.93 g, 90%). 1H NMR (CDCl3) δ 2.68 (t, 2H, J=7.2 Hz), 2.93 (t, 2H, J=7.2 Hz), 3.69 (s, 3H), 6.81 (s, 1H), 7.55 (s, 1H).

المصدر