تفاعل #68780

معادلة التفاعل

HCl

LiOH

2-acetylamino-4-phenyl-thiazole-5-carboxylic acid ethyl ester

NaOH

→

desired product

2-Acetylamino-4-phenyl-thiazole-5-carboxylic acid

المذيبات

water

ظروف التفاعل

المعالجة

1. 1
   workup.WAITto stand at rt for 2 h
2. 2
   أخرىthe precipitate is collected
3. 3
   غسيلwashed with water and ACN

الإجراء التجريبي

To 2.2 g (7.62 mmol) 2-acetylamino-4-phenyl-thiazole-5-carboxylic acid ethyl ester in 10 mL water is added 5 mL 4N NaOH and the mixture is allowed to stand at rt for 12 h. 1 g LiOH is added and the mixture is allowed to stand at rt for 2 h. The mixture is neutralized with aq. 2 N HCl solution and the precipitate is collected and washed with water and ACN to yield the desired product.

المصدر