تفاعل #55566

معادلة التفاعل

9-keto-15-hydroxy-19-methyl-prosta-13,18-dienoic acid, methyl ester

NaOH

→

9-keto-15-hydroxy-19-methyl-prosta-13,18-dienoic acid

المردود 91.5%

المذيبات

water

methanol

water

ظروف التفاعل

المعالجة

1. 1
   استخلاصextracted with diethyl ether (10 ml)
2. 2
   استخلاصextracted with diethyl ether (3×15 ml)
3. 3
   غسيلThe ethereal solution is washed with water to neutrality
4. 4
   تجفيفdried over sodium sulphate
5. 5
   أخرىthe solvent evaporated in vacuo

الإجراء التجريبي

The solution of 0.5 g of 9-keto-15-hydroxy-19-methyl-prosta-13,18-dienoic acid, methyl ester, 0.170 g of NaOH in water (1.5 ml), methanol (4.5 ml) is left for two hours at room temperature under nitrogen, then diluted with water (22 ml) and extracted with diethyl ether (10 ml). The aqueous layer is acidified (congo red) with HCl (5%), then extracted with diethyl ether (3×15 ml). The ethereal solution is washed with water to neutrality, dried over sodium sulphate and the solvent evaporated in vacuo to yield 0.44 g of 9-keto-15-hydroxy-19-methyl-prosta-13,18-dienoic acid (oil).

المصدر