تفاعل #514058

معادلة التفاعل

3-ethyl-6-(3,4-methylenedioxyphenyl)-3-hexenyl iodide

lithium

3,5-heptanedione

tetramethylurea

→

4-[3-ethyl-6-(3,4-methylenedioxyphenyl)-3-hexenyl]-3,5-heptanedione

ظروف التفاعل

المعالجة

1. 1
   تركيزconcentrated
2. 2
   أخرىto remove the solvent
3. 3
   workup.ADDITIONthe residue slurried in ether and treated with excess glacial acetic acid
4. 4
   workup.ADDITIONWater was added
5. 5
   أخرىthe ether layer separated
6. 6
   غسيلwashed with water
7. 7
   تركيزconcentrated
8. 8
   workup.DISTILLATIONThe residue was distilled in a molecular still
9. 9
   أخرىto remove volatile material at 110° C. (0.001 mml.)
10. 10
    أخرىthe non-volatile residue was chromatographed on 10 g
11. 11
    غسيلof activated magnesium silicate in benzene solution and eluted with ethyl acetate

الإجراء التجريبي

A solution of 15 g. of the lithium salt of 3,5-heptanedione (prepared as described in Example 8 below) in 100 ml. of tetramethylurea was stirred under nitrogen at room temperature, and 10 g. of 3-ethyl-6-(3,4-methylenedioxyphenyl)-3-hexenyl iodide (Preparation D1) was added. The reaction mixture was stirred for forty-eight hours, then concentrated to remove the solvent, and the residue slurried in ether and treated with excess glacial acetic acid. Water was added, the ether layer separated, washed with water and concentrated. The residue was distilled in a molecular still to remove volatile material at 110° C. (0.001 mml.), and the non-volatile residue was chromatographed on 10 g. of activated magnesium silicate in benzene solution and eluted with ethyl acetate to give 4-[3-ethyl-6-(3,4-methylenedioxyphenyl)-3-hexenyl]-3,5-heptanedione as a yellow oil.

المصدر