تفاعل #501606

معادلة التفاعل

ε-Caprolactone

trimethylene carbonate

lauryl alcohol

→

ε-Caprolactone Trimethylene Carbonate

ظروف التفاعل

المعالجة

1. 1
   أخرىThe flask was flushed with nitrogen
2. 2
   أخرىevacuated
3. 3
   أخرىsealed

الإجراء التجريبي

ε-Caprolactone (8.0 g, 0.070 mole), trimethylene carbonate (2.0 g, 0.020 mole), lauryl alcohol (0.283 g, 1.52×10-3 mole) and stannous chloride dihydrate (2.02 mg, 8.91×10-6 mole) were combined in a flask. The flask was flushed with nitrogen, evacuated and sealed. The flask was heated at 135° C. for 24 hours. The resulting polymer had a composition, as measured by 1H NMR, of 86 wt. % ε-caprolactone and 14 wt. % trimethylene carbonate. The ηinh of the copolymer was 0.26 dl/g (0.5 g/dl in HFAS).

المصدر