تفاعل #492227

معادلة التفاعل

Phenyl lithium

1,10-dibromodecane

→

oil

المردود 61.7%

10-bromodecylbenzene

المردود 61.7%

المذيبات

—

ice water

THF

ظروف التفاعل

المعالجة

1. 1
   workup.ADDITIONAfter addition
2. 2
   workup.WAITAfter 48 hours
3. 3
   أخرىit was quenched with H2O (200 mL)
4. 4
   استخلاصextracted with CH2Cl2 (200 mL×2)
5. 5
   أخرىdried
6. 6
   تركيزAfter concentration
7. 7
   workup.DISTILLATIONthe residue was distilled

الإجراء التجريبي

To a 250 mL flask in ice-water bath was added 1,10-dibromodecane (46.0 g, 153 mmol) and anhydrous THF (100 ml) under nitrogen. Phenyl lithium (1.8 M in dibutyl ether, 28.5 mL, 51 mmol) was added dropwise. After addition was completed, the reaction mixture was stirred for 1 hour and warmed to room temperature. After 48 hours, it was quenched with H2O (200 mL), extracted with CH2Cl2 (200 mL×2) and dried. After concentration, the residue was distilled to give a colorless oil (9.35 g, yield 61.7%) at 130° C./0.07 mmHg. 1H NMR (CDCl3, 500 MHz) δ=7.27-7.32 (m, 2H), 7.20 (d, J=6.5 Hz, 3H), 3.43 (t, J=7.0 Hz, 2H), 2.62 (t, J=8.0 Hz, 2H), 1.84-1.96 (m, 2H), 1.60-1.68 (m, 2H), 1.41-1.52 (m, 2H), 1.24-1.41 (m, 10H).

المصدر