تفاعل #1166469

معادلة التفاعل

N-(2-hydroxyethoxyethyl)hexahydrophthalimide

triethylamine

acryloyl chloride

→

orange-red liquid

المردود 59.5%

N-(Acryloyloxyethoxyethyl)hexahydrophthalimide

المردود 59.5%

المذيبات

acetone

ظروف التفاعل

المعالجة

1. 1
   أخرىA one liter, three necked flask was equipped with overhead stirrer
2. 2
   أخرىThe triethylamine hydrochloride salt was removed by filtration
3. 3
   أخرىthe remaining mother liquor was evaporated with a rotoevaporator
4. 4
   workup.DISSOLUTIONThe resulting red-orange liquid was dissolved in chloroform
5. 5
   استخلاصextracted with HCl(10%), NaCl(aq.), NH4OH(10%), NaCl(aq.)
6. 6
   تجفيفdried over MgSO4
7. 7
   أخرىThe chloroform was removed with a rotoevaporator

الإجراء التجريبي

A one liter, three necked flask was equipped with overhead stirrer, nitrogen atmosphere and an addition funnel. The flask was charged with 100 g of N-(2-hydroxyethoxyethyl)hexahydrophthalimide (0.41 mol.), 42 g of triethylamine (0.41 mol.), 1 g of phenothiazine and 400 ml of acetone. Next, 38 g of acryloyl chloride (0.41 mol.) was added slowly to the flask via the addition funnel over 45 minutes. The reaction was stirred for an additional 12 hours. The triethylamine hydrochloride salt was removed by filtration and the remaining mother liquor was evaporated with a rotoevaporator. The resulting red-orange liquid was dissolved in chloroform and extracted with HCl(10%), NaCl(aq.), NH4OH(10%), NaCl(aq.) and dried over MgSO4. The chloroform was removed with a rotoevaporator to yield 72 g (59%) of an orange-red liquid. The product was confirmed by IR and 13C NMR.

المصدر